Push a block and watch the free-body diagram and the resulting acceleration resolve. Every force is drawn from the block's centre — applied push, weight, normal, and friction — and their vector sum (the net force) is what actually drives the motion through ΣF = ma.
→ Applied F→ Weight mg→ Normal N→ Friction f→ Net ΣF
Setup
Applied force F24 N
Push angle α20 °
Mass m4.0 kg
Friction μ0.30
Lift acceleration a0.0 m/s²
0.00 m/s²
Acceleration
0.0
Net ΣF (N)
0.0
a (m/s²)
39.2
Normal N (N)
0.0
Friction f (N)
ΣF = maN = mg − F sinαf ≤ μN
Playback
Try this: raise μ until the block won't budge — static friction rises to match your push exactly and the net force is zero. Then tilt the push upward and watch N (and the max friction it allows) drop away.